class 10 science NCERT Solutions

 Here is a comprehensive, exam-oriented answer key for the NCERT Class 10 Science – Chapter 1: Chemical Reactions and Equations – Exercise Questions 1 to 20, explained clearly and concisely for both teaching and revision:


1. Identify incorrect statements:

Reaction:

2PbO(s)+C(s)2Pb(s)+CO2(g)2\text{PbO}(s) + \text{C}(s) \rightarrow 2\text{Pb}(s) + \text{CO}_2(g)

Correct analysis:

  • Lead oxide (PbO) is reduced to lead.

  • Carbon (C) is oxidised to CO₂.

  • CO₂ is not getting oxidised, it is a product.

Incorrect statements: (a) and (b)

Answer: (i) (a) and (b)


2. Type of reaction:

Fe2O3+2AlAl2O3+2Fe\text{Fe}_2\text{O}_3 + 2\text{Al} \rightarrow \text{Al}_2\text{O}_3 + 2\text{Fe}

Explanation: Aluminium displaces iron from its oxide → Displacement reaction

Answer: (d) displacement reaction


3. Reaction of HCl with iron filings:

Fe+2HClFeCl2+H2\text{Fe} + 2\text{HCl} \rightarrow \text{FeCl}_2 + \text{H}_2 \uparrow

Hydrogen gas and iron chloride are produced.

Answer: (a)


4. Balanced chemical equation:

A balanced chemical equation has equal number of atoms of each element on both sides.

Why balance?
To obey the Law of Conservation of Mass.


5. Translate and balance:

(a) 3H2+N22NH33\text{H}_2 + \text{N}_2 \rightarrow 2\text{NH}_3

(b) 2H2S+3O22H2O+2SO22\text{H}_2\text{S} + 3\text{O}_2 \rightarrow 2\text{H}_2\text{O} + 2\text{SO}_2

(c) 3BaCl2+Al2(SO4)32AlCl3+3BaSO43\text{BaCl}_2 + \text{Al}_2(\text{SO}_4)_3 \rightarrow 2\text{AlCl}_3 + 3\text{BaSO}_4

(d) 2K+2H2O2KOH+H22\text{K} + 2\text{H}_2\text{O} \rightarrow 2\text{KOH} + \text{H}_2 \uparrow


6. Balance these equations:

(a)

2HNO3+Ca(OH)2Ca(NO3)2+2H2O2\text{HNO}_3 + \text{Ca(OH)}_2 \rightarrow \text{Ca(NO}_3)_2 + 2\text{H}_2\text{O}

(b)

2NaOH+H2SO4Na2SO4+2H2O2\text{NaOH} + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O}

(c)

NaCl+AgNO3AgCl+NaNO3\text{NaCl} + \text{AgNO}_3 \rightarrow \text{AgCl} \downarrow + \text{NaNO}_3

(d)

BaCl2+H2SO4BaSO4+2HCl\text{BaCl}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{BaSO}_4 \downarrow + 2\text{HCl}

7. Write and balance reactions:

(a)

Ca(OH)2+CO2CaCO3+H2O\text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + \text{H}_2\text{O}

(b)

Zn+2AgNO3Zn(NO3)2+2Ag\text{Zn} + 2\text{AgNO}_3 \rightarrow \text{Zn(NO}_3)_2 + 2\text{Ag}

(c)

2Al+3CuCl22AlCl3+3Cu2\text{Al} + 3\text{CuCl}_2 \rightarrow 2\text{AlCl}_3 + 3\text{Cu}

(d)

BaCl2+K2SO4BaSO4+2KCl\text{BaCl}_2 + \text{K}_2\text{SO}_4 \rightarrow \text{BaSO}_4 \downarrow + 2\text{KCl}

8. Identify reaction types:

(a) Double Displacement (precipitation)

2KBr+BaI22KI+BaBr22\text{KBr} + \text{BaI}_2 \rightarrow 2\text{KI} + \text{BaBr}_2

(b) Thermal Decomposition

ZnCO3HeatZnO+CO2\text{ZnCO}_3 \xrightarrow{\text{Heat}} \text{ZnO} + \text{CO}_2

(c) Combination Reaction

H2+Cl22HCl\text{H}_2 + \text{Cl}_2 \rightarrow 2\text{HCl}

(d) Displacement Reaction

Mg+2HClMgCl2+H2\text{Mg} + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2

9. Exothermic vs Endothermic:

  • Exothermic Reaction: Heat is released
    Example: Combustion of fuel

  • Endothermic Reaction: Heat is absorbed
    Example: Decomposition of calcium carbonate


10. Respiration as Exothermic:

  • Glucose is oxidised in cells → Releases energy

C6H12O6+6O26CO2+6H2O+Energy\text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + 6\text{H}_2\text{O} + \text{Energy}

✅ Hence, exothermic reaction


11. Decomposition vs Combination:

  • Combination: Two/more substances → One product

    H2+Cl22HCl\text{H}_2 + \text{Cl}_2 \rightarrow 2\text{HCl}
  • Decomposition: One compound → Simpler substances

    CaCO3HeatCaO+CO2\text{CaCO}_3 \xrightarrow{\text{Heat}} \text{CaO} + \text{CO}_2

12. Decomposition Reactions (Energy-based):

  • Heat:

    2Pb(NO3)2Heat2PbO+4NO2+O22\text{Pb(NO}_3)_2 \xrightarrow{\text{Heat}} 2\text{PbO} + 4\text{NO}_2 + \text{O}_2
  • Light:

    2AgClSunlight2Ag+Cl22\text{AgCl} \xrightarrow{\text{Sunlight}} 2\text{Ag} + \text{Cl}_2
  • Electricity:

    2H2OElectricity2H2+O22\text{H}_2\text{O} \xrightarrow{\text{Electricity}} 2\text{H}_2 + \text{O}_2

13. Displacement vs Double Displacement:

  • Displacement: One element replaces another

    Zn+CuSO4ZnSO4+Cu\text{Zn} + \text{CuSO}_4 \rightarrow \text{ZnSO}_4 + \text{Cu}
  • Double Displacement: Ions are exchanged

    Na2SO4+BaCl2BaSO4+2NaCl\text{Na}_2\text{SO}_4 + \text{BaCl}_2 \rightarrow \text{BaSO}_4 \downarrow + 2\text{NaCl}

14. Silver recovery using copper:

2AgNO3+CuCu(NO3)2+2Ag2\text{AgNO}_3 + \text{Cu} \rightarrow \text{Cu(NO}_3)_2 + 2\text{Ag}

15. Precipitation Reaction:

A reaction in which insoluble solid (precipitate) forms when two solutions are mixed.
Example:

BaCl2+Na2SO4BaSO4+2NaCl\text{BaCl}_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 \downarrow + 2\text{NaCl}

16. Oxidation and Reduction (Oxygen-based):

  • Oxidation (Gain of oxygen):

    2Mg+O22MgO2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}
  • Reduction (Loss of oxygen):

    CuO+H2Cu+H2O\text{CuO} + \text{H}_2 \rightarrow \text{Cu} + \text{H}_2\text{O}

17. Shiny metal ‘X’ turns black:

  • X = Copper (Cu)

  • Black substance = Copper(II) oxide (CuO)


18. Why paint iron articles?

✅ To prevent rusting (corrosion) by blocking contact with air and moisture.


19. Why flush chips with nitrogen?

✅ To prevent rancidity by removing oxygen which causes oxidation of fats/oils.


20. Explain:

(a) Corrosion:
Slow degradation of metals due to environmental factors.
Example: Rusting of iron

(b) Rancidity:
Spoilage of food containing fats/oils due to oxidation.
Example: Spoiled ghee or oily snacks


Would you like me to create a PDF worksheet, PowerPoint slides, or quiz set based on this full chapter for your students on www.dasklibro.com?

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